Base | Representation |
---|---|
bin | 100001011100111010101000… |
… | …100101001000001100110111 |
3 | 201021220210020121100120202101 |
4 | 201130322220211020030313 |
5 | 123240424130320444031 |
6 | 1240523112403522531 |
7 | 42663155056630555 |
oct | 4134725045101467 |
9 | 637823217316671 |
10 | 147122638062391 |
11 | 429723a6785a62 |
12 | 14601429989447 |
13 | 64127b3931c44 |
14 | 2848ab8d78bd5 |
15 | 1201ee658e361 |
hex | 85cea8948337 |
147122638062391 has 2 divisors, whose sum is σ = 147122638062392. Its totient is φ = 147122638062390.
The previous prime is 147122638062343. The next prime is 147122638062467. The reversal of 147122638062391 is 193260836221741.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 147122638062391 - 215 = 147122638029623 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (147122638062331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 73561319031195 + 73561319031196.
It is an arithmetic number, because the mean of its divisors is an integer number (73561319031196).
Almost surely, 2147122638062391 is an apocalyptic number.
147122638062391 is a deficient number, since it is larger than the sum of its proper divisors (1).
147122638062391 is an equidigital number, since it uses as much as digits as its factorization.
147122638062391 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5225472, while the sum is 55.
The spelling of 147122638062391 in words is "one hundred forty-seven trillion, one hundred twenty-two billion, six hundred thirty-eight million, sixty-two thousand, three hundred ninety-one".
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