Base | Representation |
---|---|
bin | 1101011000011010100000… |
… | …1000100100001111011011 |
3 | 1221002120001002220121010011 |
4 | 3112012220020210033123 |
5 | 3412024343423303213 |
6 | 51143033011502351 |
7 | 3045661634611063 |
oct | 326065010441733 |
9 | 57076032817104 |
10 | 14713083806683 |
11 | 476286926a959 |
12 | 17975b1bb79b7 |
13 | 82958cc56822 |
14 | 38c18d2b63a3 |
15 | 1a7ac395e03d |
hex | d61a82243db |
14713083806683 has 2 divisors, whose sum is σ = 14713083806684. Its totient is φ = 14713083806682.
The previous prime is 14713083806639. The next prime is 14713083806741. The reversal of 14713083806683 is 38660838031741.
It is an a-pointer prime, because the next prime (14713083806741) can be obtained adding 14713083806683 to its sum of digits (58).
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14713083806683 is a prime.
It is not a weakly prime, because it can be changed into another prime (14713083800683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7356541903341 + 7356541903342.
It is an arithmetic number, because the mean of its divisors is an integer number (7356541903342).
Almost surely, 214713083806683 is an apocalyptic number.
14713083806683 is a deficient number, since it is larger than the sum of its proper divisors (1).
14713083806683 is an equidigital number, since it uses as much as digits as its factorization.
14713083806683 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13934592, while the sum is 58.
The spelling of 14713083806683 in words is "fourteen trillion, seven hundred thirteen billion, eighty-three million, eight hundred six thousand, six hundred eighty-three".
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