1473365771153 has 2 divisors, whose sum is σ = 1473365771154. Its totient is φ = 1473365771152.

The previous prime is 1473365771113. The next prime is 1473365771167. The reversal of 1473365771153 is 3511775633741.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1390342840384 + 83022930769 = 1179128^2 + 288137^2 .

It is a cyclic number.

It is not a de Polignac number, because 1473365771153 - 2²² = 1473361576849 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1473365771095 and 1473365771104.

It is not a weakly prime, because it can be changed into another prime (1473365771113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 736682885576 + 736682885577.

It is an arithmetic number, because the mean of its divisors is an integer number (736682885577).

Almost surely, 2^{1473365771153} is an apocalyptic number.

It is an amenable number.

1473365771153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1473365771153 is an equidigital number, since it uses as much as digits as its factorization.

1473365771153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5556600, while the sum is 53.

The spelling of 1473365771153 in words is "one trillion, four hundred seventy-three billion, three hundred sixty-five million, seven hundred seventy-one thousand, one hundred fifty-three".