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14741431483489 is a prime number
BaseRepresentation
bin1101011010000100000111…
…0010010111110001100001
31221012021012201001210011221
43112201001302113301201
53413010422424432424
651204041540535041
73051014262105124
oct326410162276141
957167181053157
1014741431483489
114773895845027
1217a0ba36b1481
1382c159bc6199
1438d6bc0ca3bb
151a86d24a09e4
hexd6841c97c61

14741431483489 has 2 divisors, whose sum is σ = 14741431483490. Its totient is φ = 14741431483488.

The previous prime is 14741431483487. The next prime is 14741431483549. The reversal of 14741431483489 is 98438413414741.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14462048410000 + 279383073489 = 3802900^2 + 528567^2 .

It is a cyclic number.

It is not a de Polignac number, because 14741431483489 - 21 = 14741431483487 is a prime.

It is a super-2 number, since 2×147414314834892 (a number of 27 digits) contains 22 as substring.

Together with 14741431483487, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (14741431483487) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7370715741744 + 7370715741745.

It is an arithmetic number, because the mean of its divisors is an integer number (7370715741745).

Almost surely, 214741431483489 is an apocalyptic number.

It is an amenable number.

14741431483489 is a deficient number, since it is larger than the sum of its proper divisors (1).

14741431483489 is an equidigital number, since it uses as much as digits as its factorization.

14741431483489 is an evil number, because the sum of its binary digits is even.

The product of its digits is 37158912, while the sum is 61.

The spelling of 14741431483489 in words is "fourteen trillion, seven hundred forty-one billion, four hundred thirty-one million, four hundred eighty-three thousand, four hundred eighty-nine".