Base | Representation |
---|---|
bin | 10101100010010111101… |
… | …011011111111101010001 |
3 | 12020111011200112101011212 |
4 | 111202113223133331101 |
5 | 143222031424400104 |
6 | 3051524145545505 |
7 | 211633054200536 |
oct | 25422753377521 |
9 | 5214150471155 |
10 | 1480013512529 |
11 | 520741053552 |
12 | 1baa05645295 |
13 | a9745790266 |
14 | 518c10a0d8d |
15 | 287728ec36e |
hex | 15897adff51 |
1480013512529 has 2 divisors, whose sum is σ = 1480013512530. Its totient is φ = 1480013512528.
The previous prime is 1480013512519. The next prime is 1480013512531. The reversal of 1480013512529 is 9252153100841.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1479920910400 + 92602129 = 1216520^2 + 9623^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1480013512529 is a prime.
Together with 1480013512531, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1480013512519) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 740006756264 + 740006756265.
It is an arithmetic number, because the mean of its divisors is an integer number (740006756265).
Almost surely, 21480013512529 is an apocalyptic number.
It is an amenable number.
1480013512529 is a deficient number, since it is larger than the sum of its proper divisors (1).
1480013512529 is an equidigital number, since it uses as much as digits as its factorization.
1480013512529 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86400, while the sum is 41.
The spelling of 1480013512529 in words is "one trillion, four hundred eighty billion, thirteen million, five hundred twelve thousand, five hundred twenty-nine".
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