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148019989493 is a prime number
BaseRepresentation
bin1000100111011010101…
…1011100101111110101
3112011001202201120002002
42021312223130233311
54411121104130433
6151555514025045
713460034102605
oct2116653345765
9464052646062
10148019989493
1157858474a32
122482b718185
1310c5c2b37cc
14724281ac05
153cb4d699e8
hex2276adcbf5

148019989493 has 2 divisors, whose sum is σ = 148019989494. Its totient is φ = 148019989492.

The previous prime is 148019989489. The next prime is 148019989511. The reversal of 148019989493 is 394989910841.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 74222463844 + 73797525649 = 272438^2 + 271657^2 .

It is a cyclic number.

It is not a de Polignac number, because 148019989493 - 22 = 148019989489 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (148019989463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74009994746 + 74009994747.

It is an arithmetic number, because the mean of its divisors is an integer number (74009994747).

Almost surely, 2148019989493 is an apocalyptic number.

It is an amenable number.

148019989493 is a deficient number, since it is larger than the sum of its proper divisors (1).

148019989493 is an equidigital number, since it uses as much as digits as its factorization.

148019989493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20155392, while the sum is 65.

The spelling of 148019989493 in words is "one hundred forty-eight billion, nineteen million, nine hundred eighty-nine thousand, four hundred ninety-three".