Base | Representation |
---|---|
bin | 1000100111011011111… |
… | …1100101010111010111 |
3 | 112011002010122201101011 |
4 | 2021312333211113113 |
5 | 4411123432031141 |
6 | 152000223113051 |
7 | 13460130005101 |
oct | 2116677452727 |
9 | 464063581334 |
10 | 148025267671 |
11 | 5786044a566 |
12 | 24831442787 |
13 | 10c604110a8 |
14 | 72433d2571 |
15 | 3cb555d881 |
hex | 2276fe55d7 |
148025267671 has 2 divisors, whose sum is σ = 148025267672. Its totient is φ = 148025267670.
The previous prime is 148025267657. The next prime is 148025267699. The reversal of 148025267671 is 176762520841.
It is a weak prime.
It is an emirp because it is prime and its reverse (176762520841) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 148025267671 - 213 = 148025259479 is a prime.
It is a super-2 number, since 2×1480252676712 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (148025267471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74012633835 + 74012633836.
It is an arithmetic number, because the mean of its divisors is an integer number (74012633836).
Almost surely, 2148025267671 is an apocalyptic number.
148025267671 is a deficient number, since it is larger than the sum of its proper divisors (1).
148025267671 is an equidigital number, since it uses as much as digits as its factorization.
148025267671 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1128960, while the sum is 49.
The spelling of 148025267671 in words is "one hundred forty-eight billion, twenty-five million, two hundred sixty-seven thousand, six hundred seventy-one".
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