Search a number
-
+
14811125925649 is a prime number
BaseRepresentation
bin1101011110000111101111…
…1001100100011100010001
31221102221002211110021111111
43113201323321210130101
53420131141214110044
651300045354413321
73056032336066444
oct327417371443421
957387084407444
1014811125925649
1147a03aa506a59
1217b25b4131241
138358b5c48081
14392c102c365b
151aa410d55b34
hexd787be64711

14811125925649 has 2 divisors, whose sum is σ = 14811125925650. Its totient is φ = 14811125925648.

The previous prime is 14811125925637. The next prime is 14811125925671. The reversal of 14811125925649 is 94652952111841.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12655094760000 + 2156031165649 = 3557400^2 + 1468343^2 .

It is an emirp because it is prime and its reverse (94652952111841) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14811125925649 - 231 = 14808978442001 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14811125925593 and 14811125925602.

It is not a weakly prime, because it can be changed into another prime (14811125925749) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7405562962824 + 7405562962825.

It is an arithmetic number, because the mean of its divisors is an integer number (7405562962825).

Almost surely, 214811125925649 is an apocalyptic number.

It is an amenable number.

14811125925649 is a deficient number, since it is larger than the sum of its proper divisors (1).

14811125925649 is an equidigital number, since it uses as much as digits as its factorization.

14811125925649 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6220800, while the sum is 58.

The spelling of 14811125925649 in words is "fourteen trillion, eight hundred eleven billion, one hundred twenty-five million, nine hundred twenty-five thousand, six hundred forty-nine".