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1481189871319 is a prime number
BaseRepresentation
bin10101100011011101110…
…010111100111011010111
312020121012200001121001221
4111203131302330323113
5143231434101340234
63052241011231211
7212004160113154
oct25433562747327
95217180047057
101481189871319
115211950822a4
121bb0935a8507
13a98a23c7b52
14519933d922b
15287e0d17eb4
hex158ddcbced7

1481189871319 has 2 divisors, whose sum is σ = 1481189871320. Its totient is φ = 1481189871318.

The previous prime is 1481189871313. The next prime is 1481189871323. The reversal of 1481189871319 is 9131789811841.

It is a strong prime.

It is an emirp because it is prime and its reverse (9131789811841) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1481189871319 - 219 = 1481189347031 is a prime.

It is a super-2 number, since 2×14811898713192 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1481189871313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 740594935659 + 740594935660.

It is an arithmetic number, because the mean of its divisors is an integer number (740594935660).

Almost surely, 21481189871319 is an apocalyptic number.

1481189871319 is a deficient number, since it is larger than the sum of its proper divisors (1).

1481189871319 is an equidigital number, since it uses as much as digits as its factorization.

1481189871319 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3483648, while the sum is 61.

The spelling of 1481189871319 in words is "one trillion, four hundred eighty-one billion, one hundred eighty-nine million, eight hundred seventy-one thousand, three hundred nineteen".