Base | Representation |
---|---|
bin | 10101100011101111001… |
… | …010110100010011101011 |
3 | 12020121221222111202010102 |
4 | 111203233022310103223 |
5 | 143233033210341024 |
6 | 3052325542340015 |
7 | 212014326421403 |
oct | 25435712642353 |
9 | 5217858452112 |
10 | 1481481340139 |
11 | 52132465a119 |
12 | 1bb15512a60b |
13 | a991a8c97c8 |
14 | 519bddcb803 |
15 | 2880b6de1ae |
hex | 158ef2b44eb |
1481481340139 has 2 divisors, whose sum is σ = 1481481340140. Its totient is φ = 1481481340138.
The previous prime is 1481481340127. The next prime is 1481481340277. The reversal of 1481481340139 is 9310431841841.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1481481340139 - 24 = 1481481340123 is a prime.
It is a super-2 number, since 2×14814813401392 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1481481340093 and 1481481340102.
It is not a weakly prime, because it can be changed into another prime (1481481340639) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 740740670069 + 740740670070.
It is an arithmetic number, because the mean of its divisors is an integer number (740740670070).
Almost surely, 21481481340139 is an apocalyptic number.
1481481340139 is a deficient number, since it is larger than the sum of its proper divisors (1).
1481481340139 is an equidigital number, since it uses as much as digits as its factorization.
1481481340139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 331776, while the sum is 47.
The spelling of 1481481340139 in words is "one trillion, four hundred eighty-one billion, four hundred eighty-one million, three hundred forty thousand, one hundred thirty-nine".
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