Base | Representation |
---|---|
bin | 10101100110011110100… |
… | …111011000100100111011 |
3 | 12020220120010020002221111 |
4 | 111212132213120210323 |
5 | 143310100224412111 |
6 | 3053534012021151 |
7 | 212150300652202 |
oct | 25463647304473 |
9 | 5226503202844 |
10 | 1484424841531 |
11 | 5225a51402a5 |
12 | 1bb836a617b7 |
13 | a9c9968b9c8 |
14 | 51bbccc8239 |
15 | 2892ed22a21 |
hex | 1599e9d893b |
1484424841531 has 2 divisors, whose sum is σ = 1484424841532. Its totient is φ = 1484424841530.
The previous prime is 1484424841453. The next prime is 1484424841553. The reversal of 1484424841531 is 1351484244841.
It is a strong prime.
It is an emirp because it is prime and its reverse (1351484244841) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1484424841531 - 233 = 1475834906939 is a prime.
It is a super-2 number, since 2×14844248415312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1484424841631) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 742212420765 + 742212420766.
It is an arithmetic number, because the mean of its divisors is an integer number (742212420766).
Almost surely, 21484424841531 is an apocalyptic number.
1484424841531 is a deficient number, since it is larger than the sum of its proper divisors (1).
1484424841531 is an equidigital number, since it uses as much as digits as its factorization.
1484424841531 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1966080, while the sum is 49.
The spelling of 1484424841531 in words is "one trillion, four hundred eighty-four billion, four hundred twenty-four million, eight hundred forty-one thousand, five hundred thirty-one".
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