Search a number
-
+
1484424841553 is a prime number
BaseRepresentation
bin10101100110011110100…
…111011000100101010001
312020220120010020002222022
4111212132213120211101
5143310100224412203
63053534012021225
7212150300652233
oct25463647304521
95226503202868
101484424841553
115225a5140315
121bb836a61815
13a9c9968ba14
1451bbccc8253
152892ed22a38
hex1599e9d8951

1484424841553 has 2 divisors, whose sum is σ = 1484424841554. Its totient is φ = 1484424841552.

The previous prime is 1484424841531. The next prime is 1484424841589. The reversal of 1484424841553 is 3551484244841.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1470284777809 + 14140063744 = 1212553^2 + 118912^2 .

It is a cyclic number.

It is not a de Polignac number, because 1484424841553 - 212 = 1484424837457 is a prime.

It is a super-2 number, since 2×14844248415532 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1484424841495 and 1484424841504.

It is not a weakly prime, because it can be changed into another prime (1484424841153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 742212420776 + 742212420777.

It is an arithmetic number, because the mean of its divisors is an integer number (742212420777).

Almost surely, 21484424841553 is an apocalyptic number.

It is an amenable number.

1484424841553 is a deficient number, since it is larger than the sum of its proper divisors (1).

1484424841553 is an equidigital number, since it uses as much as digits as its factorization.

1484424841553 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 9830400, while the sum is 53.

The spelling of 1484424841553 in words is "one trillion, four hundred eighty-four billion, four hundred twenty-four million, eight hundred forty-one thousand, five hundred fifty-three".