Base | Representation |
---|---|
bin | 1000101001011010100… |
… | …1011000101000110011 |
3 | 112012110010220221020101 |
4 | 2022112221120220303 |
5 | 4413220404204113 |
6 | 152125033253231 |
7 | 13506235610401 |
oct | 2122651305063 |
9 | 465403827211 |
10 | 148556319283 |
11 | 58003195499 |
12 | 2495b264217 |
13 | 11016448a08 |
14 | 7293b4c471 |
15 | 3ce6eac2dd |
hex | 2296a58a33 |
148556319283 has 2 divisors, whose sum is σ = 148556319284. Its totient is φ = 148556319282.
The previous prime is 148556319281. The next prime is 148556319311. The reversal of 148556319283 is 382913655841.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 148556319283 - 21 = 148556319281 is a prime.
Together with 148556319281, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (148556319281) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74278159641 + 74278159642.
It is an arithmetic number, because the mean of its divisors is an integer number (74278159642).
Almost surely, 2148556319283 is an apocalyptic number.
148556319283 is a deficient number, since it is larger than the sum of its proper divisors (1).
148556319283 is an equidigital number, since it uses as much as digits as its factorization.
148556319283 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6220800, while the sum is 55.
The spelling of 148556319283 in words is "one hundred forty-eight billion, five hundred fifty-six million, three hundred nineteen thousand, two hundred eighty-three".
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