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148622113889 is a prime number
BaseRepresentation
bin1000101001101010010…
…0010111110001100001
3112012121201201122110122
42022122210113301201
54413334230121024
6152135343410025
713510665060404
oct2123244276141
9465551648418
10148622113889
11580373439a7
12249792b3915
1311026c74332
14729c797d3b
153cecb56d5e
hex229a917c61

148622113889 has 2 divisors, whose sum is σ = 148622113890. Its totient is φ = 148622113888.

The previous prime is 148622113873. The next prime is 148622113901. The reversal of 148622113889 is 988311226841.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99734692864 + 48887421025 = 315808^2 + 221105^2 .

It is a cyclic number.

It is not a de Polignac number, because 148622113889 - 24 = 148622113873 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 148622113889.

It is not a weakly prime, because it can be changed into another prime (148622113859) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74311056944 + 74311056945.

It is an arithmetic number, because the mean of its divisors is an integer number (74311056945).

Almost surely, 2148622113889 is an apocalyptic number.

It is an amenable number.

148622113889 is a deficient number, since it is larger than the sum of its proper divisors (1).

148622113889 is an equidigital number, since it uses as much as digits as its factorization.

148622113889 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1327104, while the sum is 53.

The spelling of 148622113889 in words is "one hundred forty-eight billion, six hundred twenty-two million, one hundred thirteen thousand, eight hundred eighty-nine".