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1487162113 is a prime number
BaseRepresentation
bin101100010100100…
…0100101100000001
310211122100122220021
41120221010230001
511021203141423
6403323013441
751565445413
oct13051045401
93748318807
101487162113
116a35119a8
1235606a281
131a9148aa8
141017209b3
158a86095d
hex58a44b01

1487162113 has 2 divisors, whose sum is σ = 1487162114. Its totient is φ = 1487162112.

The previous prime is 1487162069. The next prime is 1487162141. The reversal of 1487162113 is 3112617841.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1139265009 + 347897104 = 33753^2 + 18652^2 .

It is an emirp because it is prime and its reverse (3112617841) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1487162113 - 221 = 1485064961 is a prime.

It is not a weakly prime, because it can be changed into another prime (1487162153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 743581056 + 743581057.

It is an arithmetic number, because the mean of its divisors is an integer number (743581057).

Almost surely, 21487162113 is an apocalyptic number.

It is an amenable number.

1487162113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1487162113 is an equidigital number, since it uses as much as digits as its factorization.

1487162113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 8064, while the sum is 34.

The square root of 1487162113 is about 38563.7409103422. The cubic root of 1487162113 is about 1141.4391675654.

Adding to 1487162113 its reverse (3112617841), we get a palindrome (4599779954).

The spelling of 1487162113 in words is "one billion, four hundred eighty-seven million, one hundred sixty-two thousand, one hundred thirteen".