Base | Representation |
---|---|
bin | 11011101101111010… |
… | …00011000000100001 |
3 | 1102102001111122021202 |
4 | 31312331003000201 |
5 | 220433414211411 |
6 | 10500331130545 |
7 | 1034520103343 |
oct | 156675030041 |
9 | 42361448252 |
10 | 14880616481 |
11 | 63467a1455 |
12 | 2a735a3a55 |
13 | 1531ba9913 |
14 | a12429293 |
15 | 5c15d183b |
hex | 376f43021 |
14880616481 has 2 divisors, whose sum is σ = 14880616482. Its totient is φ = 14880616480.
The previous prime is 14880616349. The next prime is 14880616489. The reversal of 14880616481 is 18461608841.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8349390625 + 6531225856 = 91375^2 + 80816^2 .
It is a cyclic number.
It is not a de Polignac number, because 14880616481 - 222 = 14876422177 is a prime.
It is a super-3 number, since 3×148806164813 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (14880616489) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7440308240 + 7440308241.
It is an arithmetic number, because the mean of its divisors is an integer number (7440308241).
Almost surely, 214880616481 is an apocalyptic number.
It is an amenable number.
14880616481 is a deficient number, since it is larger than the sum of its proper divisors (1).
14880616481 is an equidigital number, since it uses as much as digits as its factorization.
14880616481 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 294912, while the sum is 47.
The spelling of 14880616481 in words is "fourteen billion, eight hundred eighty million, six hundred sixteen thousand, four hundred eighty-one".
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