Base | Representation |
---|---|
bin | 11011110000010111… |
… | …10011111011110001 |
3 | 1102110111100122111212 |
4 | 31320023303323301 |
5 | 221004210422423 |
6 | 10502345445505 |
7 | 1035160440461 |
oct | 157013637361 |
9 | 42414318455 |
10 | 14901264113 |
11 | 635741430a |
12 | 2a7a4a0895 |
13 | 1536258a58 |
14 | a15081ba1 |
15 | 5c330e578 |
hex | 3782f3ef1 |
14901264113 has 2 divisors, whose sum is σ = 14901264114. Its totient is φ = 14901264112.
The previous prime is 14901264107. The next prime is 14901264139. The reversal of 14901264113 is 31146210941.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14900596624 + 667489 = 122068^2 + 817^2 .
It is a cyclic number.
It is not a de Polignac number, because 14901264113 - 210 = 14901263089 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 14901264113.
It is not a weakly prime, because it can be changed into another prime (14901264143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7450632056 + 7450632057.
It is an arithmetic number, because the mean of its divisors is an integer number (7450632057).
Almost surely, 214901264113 is an apocalyptic number.
It is an amenable number.
14901264113 is a deficient number, since it is larger than the sum of its proper divisors (1).
14901264113 is an equidigital number, since it uses as much as digits as its factorization.
14901264113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 32.
The spelling of 14901264113 in words is "fourteen billion, nine hundred one million, two hundred sixty-four thousand, one hundred thirteen".
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