1491159272441 has 2 divisors, whose sum is σ = 1491159272442. Its totient is φ = 1491159272440.

The previous prime is 1491159272413. The next prime is 1491159272443. The reversal of 1491159272441 is 1442729511941.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1131183272041 + 359976000400 = 1063571^2 + 599980^2 .

It is a cyclic number.

It is not a de Polignac number, because 1491159272441 - 2²² = 1491155078137 is a prime.

It is a super-3 number, since 3×1491159272441³ (a number of 37 digits) contains 333 as substring.

Together with 1491159272443, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1491159272441.

It is not a weakly prime, because it can be changed into another prime (1491159272443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 745579636220 + 745579636221.

It is an arithmetic number, because the mean of its divisors is an integer number (745579636221).

Almost surely, 2^{1491159272441} is an apocalyptic number.

It is an amenable number.

1491159272441 is a deficient number, since it is larger than the sum of its proper divisors (1).

1491159272441 is an equidigital number, since it uses as much as digits as its factorization.

1491159272441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 725760, while the sum is 50.

The spelling of 1491159272441 in words is "one trillion, four hundred ninety-one billion, one hundred fifty-nine million, two hundred seventy-two thousand, four hundred forty-one".