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149130127 is a prime number
BaseRepresentation
bin10001110001110…
…00101110001111
3101101121121002001
420320320232033
5301134131002
622444213131
73460404466
oct1070705617
9341547061
10149130127
11771a8743
1241b3a1a7
1324b85ca3
1415b3d9dd
15d15ba87
hex8e38b8f

149130127 has 2 divisors, whose sum is σ = 149130128. Its totient is φ = 149130126.

The previous prime is 149130101. The next prime is 149130139. The reversal of 149130127 is 721031941.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 149130127 - 211 = 149128079 is a prime.

It is a super-2 number, since 2×1491301272 = 44479589558072258, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 149130095 and 149130104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (149130197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74565063 + 74565064.

It is an arithmetic number, because the mean of its divisors is an integer number (74565064).

Almost surely, 2149130127 is an apocalyptic number.

149130127 is a deficient number, since it is larger than the sum of its proper divisors (1).

149130127 is an equidigital number, since it uses as much as digits as its factorization.

149130127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512, while the sum is 28.

The square root of 149130127 is about 12211.8846620823. The cubic root of 149130127 is about 530.3002060950.

The spelling of 149130127 in words is "one hundred forty-nine million, one hundred thirty thousand, one hundred twenty-seven".