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149194295581 is a prime number
BaseRepresentation
bin1000101011110010101…
…1000100100100011101
3112021002121101111012011
42022330223010210131
54421022214424311
6152312223311221
713531113405532
oct2127453044435
9467077344164
10149194295581
1158300321531
1224ab8a4b511
13110b867cc96
14731477cd89
153d32ecc321
hex22bcac491d

149194295581 has 2 divisors, whose sum is σ = 149194295582. Its totient is φ = 149194295580.

The previous prime is 149194295567. The next prime is 149194295617. The reversal of 149194295581 is 185592491941.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 144939342681 + 4254952900 = 380709^2 + 65230^2 .

It is an emirp because it is prime and its reverse (185592491941) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 149194295581 - 227 = 149060077853 is a prime.

It is a super-2 number, since 2×1491942955812 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (149194295281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74597147790 + 74597147791.

It is an arithmetic number, because the mean of its divisors is an integer number (74597147791).

Almost surely, 2149194295581 is an apocalyptic number.

It is an amenable number.

149194295581 is a deficient number, since it is larger than the sum of its proper divisors (1).

149194295581 is an equidigital number, since it uses as much as digits as its factorization.

149194295581 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4665600, while the sum is 58.

The spelling of 149194295581 in words is "one hundred forty-nine billion, one hundred ninety-four million, two hundred ninety-five thousand, five hundred eighty-one".