Base | Representation |
---|---|
bin | 1000101100000001110… |
… | …0100011101011010111 |
3 | 112021021000111200010021 |
4 | 2023000130203223113 |
5 | 4421134421142303 |
6 | 152322404210011 |
7 | 13532512443622 |
oct | 2130034435327 |
9 | 467230450107 |
10 | 149257599703 |
11 | 58333029893 |
12 | 24b16099907 |
13 | 110c8815b44 |
14 | 731cd3adb9 |
15 | 3d38833ebd |
hex | 22c0723ad7 |
149257599703 has 2 divisors, whose sum is σ = 149257599704. Its totient is φ = 149257599702.
The previous prime is 149257599691. The next prime is 149257599713. The reversal of 149257599703 is 307995752941.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 149257599703 - 29 = 149257599191 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (149257599713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74628799851 + 74628799852.
It is an arithmetic number, because the mean of its divisors is an integer number (74628799852).
Almost surely, 2149257599703 is an apocalyptic number.
149257599703 is a deficient number, since it is larger than the sum of its proper divisors (1).
149257599703 is an equidigital number, since it uses as much as digits as its factorization.
149257599703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21432600, while the sum is 61.
The spelling of 149257599703 in words is "one hundred forty-nine billion, two hundred fifty-seven million, five hundred ninety-nine thousand, seven hundred three".
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