Base | Representation |
---|---|
bin | 11011110011100101… |
… | …01011101010000111 |
3 | 1102112101002201012012 |
4 | 31321302223222013 |
5 | 221033111343142 |
6 | 10505151444435 |
7 | 1035635604332 |
oct | 157162535207 |
9 | 42471081165 |
10 | 14928231047 |
11 | 6370662a34 |
12 | 2a8752671b |
13 | 153ba0b312 |
14 | a188a1619 |
15 | 5c5889882 |
hex | 379caba87 |
14928231047 has 2 divisors, whose sum is σ = 14928231048. Its totient is φ = 14928231046.
The previous prime is 14928230987. The next prime is 14928231053. The reversal of 14928231047 is 74013282941.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14928231047 is a prime.
It is a super-2 number, since 2×149282310472 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14928230995 and 14928231013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14928231067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7464115523 + 7464115524.
It is an arithmetic number, because the mean of its divisors is an integer number (7464115524).
Almost surely, 214928231047 is an apocalyptic number.
14928231047 is a deficient number, since it is larger than the sum of its proper divisors (1).
14928231047 is an equidigital number, since it uses as much as digits as its factorization.
14928231047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96768, while the sum is 41.
The spelling of 14928231047 in words is "fourteen billion, nine hundred twenty-eight million, two hundred thirty-one thousand, forty-seven".
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