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14928231209 is a prime number
BaseRepresentation
bin11011110011100101…
…01011101100101001
31102112101002201102012
431321302223230221
5221033111344314
610505151445305
71035635604653
oct157162535451
942471081365
1014928231209
116370663071
122a87526835
13153ba0b408
14a188a16d3
155c588993e
hex379cabb29

14928231209 has 2 divisors, whose sum is σ = 14928231210. Its totient is φ = 14928231208.

The previous prime is 14928231137. The next prime is 14928231211. The reversal of 14928231209 is 90213282941.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13612355584 + 1315875625 = 116672^2 + 36275^2 .

It is an emirp because it is prime and its reverse (90213282941) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14928231209 is a prime.

Together with 14928231211, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14928531209) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7464115604 + 7464115605.

It is an arithmetic number, because the mean of its divisors is an integer number (7464115605).

Almost surely, 214928231209 is an apocalyptic number.

It is an amenable number.

14928231209 is a deficient number, since it is larger than the sum of its proper divisors (1).

14928231209 is an equidigital number, since it uses as much as digits as its factorization.

14928231209 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 62208, while the sum is 41.

The spelling of 14928231209 in words is "fourteen billion, nine hundred twenty-eight million, two hundred thirty-one thousand, two hundred nine".