14932048841 has 2 divisors, whose sum is σ = 14932048842. Its totient is φ = 14932048840.

The previous prime is 14932048823. The next prime is 14932048843. The reversal of 14932048841 is 14884023941.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13364284816 + 1567764025 = 115604^2 + 39595^2 .

It is a cyclic number.

It is not a de Polignac number, because 14932048841 - 2⁶ = 14932048777 is a prime.

It is a super-3 number, since 3×14932048841³ (a number of 31 digits) contains 333 as substring.

Together with 14932048843, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14932048792 and 14932048801.

It is not a weakly prime, because it can be changed into another prime (14932048843) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7466024420 + 7466024421.

It is an arithmetic number, because the mean of its divisors is an integer number (7466024421).

Almost surely, 2^14932048841 is an apocalyptic number.

It is an amenable number.

14932048841 is a deficient number, since it is larger than the sum of its proper divisors (1).

14932048841 is an equidigital number, since it uses as much as digits as its factorization.

14932048841 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 221184, while the sum is 44.

Subtracting from 14932048841 its reverse (14884023941), we obtain a triangular number (48024900 = T₉₈₀₀).

The spelling of 14932048841 in words is "fourteen billion, nine hundred thirty-two million, forty-eight thousand, eight hundred forty-one".