Base | Representation |
---|---|
bin | 111000111110… |
… | …000001010111 |
3 | 1001002201201221 |
4 | 320332001113 |
5 | 12310342403 |
6 | 1252031211 |
7 | 240636442 |
oct | 70760127 |
9 | 31081657 |
10 | 14934103 |
11 | 8480238 |
12 | 5002507 |
13 | 312b662 |
14 | 1daa659 |
15 | 149edbd |
hex | e3e057 |
14934103 has 4 divisors (see below), whose sum is σ = 15000120. Its totient is φ = 14868088.
The previous prime is 14934091. The next prime is 14934113. The reversal of 14934103 is 30143941.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30143941 = 17 ⋅1773173.
It is a cyclic number.
It is not a de Polignac number, because 14934103 - 25 = 14934071 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14934113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32668 + ... + 33121.
It is an arithmetic number, because the mean of its divisors is an integer number (3750030).
Almost surely, 214934103 is an apocalyptic number.
14934103 is a deficient number, since it is larger than the sum of its proper divisors (66017).
14934103 is an equidigital number, since it uses as much as digits as its factorization.
14934103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66016.
The product of its (nonzero) digits is 1296, while the sum is 25.
The square root of 14934103 is about 3864.4667161201. The cubic root of 14934103 is about 246.2595306677.
The spelling of 14934103 in words is "fourteen million, nine hundred thirty-four thousand, one hundred three".
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