Base | Representation |
---|---|
bin | 10001110011011… |
… | …00010000010111 |
3 | 101102000022121211 |
4 | 20321230100113 |
5 | 301212404312 |
6 | 22452522251 |
7 | 3462244051 |
oct | 1071542027 |
9 | 342008554 |
10 | 149341207 |
11 | 77332294 |
12 | 42020387 |
13 | 24c2b0a2 |
14 | 15b968d1 |
15 | d19e3a7 |
hex | 8e6c417 |
149341207 has 2 divisors, whose sum is σ = 149341208. Its totient is φ = 149341206.
The previous prime is 149341189. The next prime is 149341211. The reversal of 149341207 is 702143941.
It is a strong prime.
It is an emirp because it is prime and its reverse (702143941) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 149341207 - 211 = 149339159 is a prime.
It is a super-2 number, since 2×1493412072 = 44605592216433698, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (149341217) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74670603 + 74670604.
It is an arithmetic number, because the mean of its divisors is an integer number (74670604).
Almost surely, 2149341207 is an apocalyptic number.
149341207 is a deficient number, since it is larger than the sum of its proper divisors (1).
149341207 is an equidigital number, since it uses as much as digits as its factorization.
149341207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 31.
The square root of 149341207 is about 12220.5240067683. The cubic root of 149341207 is about 530.5502852253.
The spelling of 149341207 in words is "one hundred forty-nine million, three hundred forty-one thousand, two hundred seven".
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