Base | Representation |
---|---|
bin | 1000101100101001011… |
… | …1010011100000011111 |
3 | 112021200121121102102202 |
4 | 2023022113103200133 |
5 | 4422010020314121 |
6 | 152351110442115 |
7 | 13536603000062 |
oct | 2131227234037 |
9 | 467617542382 |
10 | 149423994911 |
11 | 58408a49a94 |
12 | 24b6196333b |
13 | 11124135449 |
14 | 73370928d9 |
15 | 3d4825140b |
hex | 22ca5d381f |
149423994911 has 2 divisors, whose sum is σ = 149423994912. Its totient is φ = 149423994910.
The previous prime is 149423994883. The next prime is 149423994919. The reversal of 149423994911 is 119499324941.
149423994911 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (119499324941) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 149423994911 - 214 = 149423978527 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (149423994919) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74711997455 + 74711997456.
It is an arithmetic number, because the mean of its divisors is an integer number (74711997456).
Almost surely, 2149423994911 is an apocalyptic number.
149423994911 is a deficient number, since it is larger than the sum of its proper divisors (1).
149423994911 is an equidigital number, since it uses as much as digits as its factorization.
149423994911 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2519424, while the sum is 56.
The spelling of 149423994911 in words is "one hundred forty-nine billion, four hundred twenty-three million, nine hundred ninety-four thousand, nine hundred eleven".
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