Base | Representation |
---|---|
bin | 10101101111101100010… |
… | …110001100100110011111 |
3 | 12021212002122122000122122 |
4 | 111233230112030212133 |
5 | 143440331114042341 |
6 | 3102251451533155 |
7 | 212650421006525 |
oct | 25575426144637 |
9 | 5255078560578 |
10 | 1494318893471 |
11 | 526812070a28 |
12 | 20173845a1bb |
13 | aabb5432201 |
14 | 5247ad4c315 |
15 | 28d0d75394b |
hex | 15bec58c99f |
1494318893471 has 2 divisors, whose sum is σ = 1494318893472. Its totient is φ = 1494318893470.
The previous prime is 1494318893467. The next prime is 1494318893491. The reversal of 1494318893471 is 1743988134941.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1494318893471 - 22 = 1494318893467 is a prime.
It is a super-4 number, since 4×14943188934714 (a number of 50 digits) contains 4444 as substring. Note that it is a super-d number also for d = 3.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1494318893491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 747159446735 + 747159446736.
It is an arithmetic number, because the mean of its divisors is an integer number (747159446736).
Almost surely, 21494318893471 is an apocalyptic number.
1494318893471 is a deficient number, since it is larger than the sum of its proper divisors (1).
1494318893471 is an equidigital number, since it uses as much as digits as its factorization.
1494318893471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 20901888, while the sum is 62.
The spelling of 1494318893471 in words is "one trillion, four hundred ninety-four billion, three hundred eighteen million, eight hundred ninety-three thousand, four hundred seventy-one".
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