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149551142400 = 293652113147
BaseRepresentation
bin1000101101000111110…
…0010101011000000000
3112022000110212012000000
42023101330111120000
54422240043024100
6152411452000000
713543005510342
oct2132174253000
9468013765000
10149551142400
11584737a2860
1224b98460000
131114459274a
147349d0d292
153d544b9900
hex22d1f15600

149551142400 has 1680 divisors, whose sum is σ = 638895679488. Its totient is φ = 34338816000.

The previous prime is 149551142333. The next prime is 149551142437. The reversal of 149551142400 is 4241155941.

149551142400 is a `hidden beast` number, since 14 + 95 + 511 + 4 + 2 + 40 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 167 ways as a sum of consecutive naturals, for example, 3181939177 + ... + 3181939223.

Almost surely, 2149551142400 is an apocalyptic number.

149551142400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 149551142400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (319447839744).

149551142400 is an abundant number, since it is smaller than the sum of its proper divisors (489344537088).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

149551142400 is an equidigital number, since it uses as much as digits as its factorization.

149551142400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 135 (or 99 counting only the distinct ones).

The product of its (nonzero) digits is 28800, while the sum is 36.

The spelling of 149551142400 in words is "one hundred forty-nine billion, five hundred fifty-one million, one hundred forty-two thousand, four hundred".