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14971480169 is a prime number
BaseRepresentation
bin11011111000101111…
…01010100001101001
31102122101110222211112
431330113222201221
5221130144331134
610513334440105
71040002324142
oct157427524151
942571428745
1014971480169
116393012708
122a99b03035
131547971a09
14a2051cac9
155c957e1ce
hex37c5ea869

14971480169 has 2 divisors, whose sum is σ = 14971480170. Its totient is φ = 14971480168.

The previous prime is 14971480129. The next prime is 14971480171. The reversal of 14971480169 is 96108417941.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13650884569 + 1320595600 = 116837^2 + 36340^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14971480169 is a prime.

It is a super-2 number, since 2×149714801692 (a number of 21 digits) contains 22 as substring.

Together with 14971480171, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14971480129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7485740084 + 7485740085.

It is an arithmetic number, because the mean of its divisors is an integer number (7485740085).

Almost surely, 214971480169 is an apocalyptic number.

It is an amenable number.

14971480169 is a deficient number, since it is larger than the sum of its proper divisors (1).

14971480169 is an equidigital number, since it uses as much as digits as its factorization.

14971480169 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 435456, while the sum is 50.

The spelling of 14971480169 in words is "fourteen billion, nine hundred seventy-one million, four hundred eighty thousand, one hundred sixty-nine".