Base | Representation |
---|---|
bin | 11011111010111011… |
… | …11110101000111001 |
3 | 1102200200011110102101 |
4 | 31331131332220321 |
5 | 221144404201013 |
6 | 10515233503401 |
7 | 1040315104123 |
oct | 157535765071 |
9 | 42620143371 |
10 | 14989912633 |
11 | 63a2462253 |
12 | 2aa4111b61 |
13 | 154b7267b7 |
14 | a22b5a213 |
15 | 5caec08dd |
hex | 37d77ea39 |
14989912633 has 2 divisors, whose sum is σ = 14989912634. Its totient is φ = 14989912632.
The previous prime is 14989912607. The next prime is 14989912681. The reversal of 14989912633 is 33621998941.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14618502649 + 371409984 = 120907^2 + 19272^2 .
It is a cyclic number.
It is not a de Polignac number, because 14989912633 - 29 = 14989912121 is a prime.
It is not a weakly prime, because it can be changed into another prime (14989913633) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7494956316 + 7494956317.
It is an arithmetic number, because the mean of its divisors is an integer number (7494956317).
Almost surely, 214989912633 is an apocalyptic number.
It is an amenable number.
14989912633 is a deficient number, since it is larger than the sum of its proper divisors (1).
14989912633 is an equidigital number, since it uses as much as digits as its factorization.
14989912633 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2519424, while the sum is 55.
The spelling of 14989912633 in words is "fourteen billion, nine hundred eighty-nine million, nine hundred twelve thousand, six hundred thirty-three".
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