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150001144341 = 3190126302147
BaseRepresentation
bin1000101110110011000…
…0111101001000010101
3112100011211121122121120
42023230300331020111
54424200243104331
6152524245034153
713560111455346
oct2135460751025
9470154548546
10150001144341
115868480a994
12250a30b5959
13111b6890299
14738d9ac0cd
153d7dc58796
hex22ecc3d215

150001144341 has 8 divisors (see below), whose sum is σ = 200106741984. Its totient is φ = 99948154800.

The previous prime is 150001144187. The next prime is 150001144441. The reversal of 150001144341 is 143441100051.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 150001144341 - 215 = 150001111573 is a prime.

It is a super-3 number, since 3×1500011443413 (a number of 35 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (150001144441) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13145371 + ... + 13156776.

It is an arithmetic number, because the mean of its divisors is an integer number (25013342748).

Almost surely, 2150001144341 is an apocalyptic number.

It is an amenable number.

150001144341 is a deficient number, since it is larger than the sum of its proper divisors (50105597643).

150001144341 is a wasteful number, since it uses less digits than its factorization.

150001144341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26304051.

The product of its (nonzero) digits is 960, while the sum is 24.

Adding to 150001144341 its reverse (143441100051), we get a palindrome (293442244392).

The spelling of 150001144341 in words is "one hundred fifty billion, one million, one hundred forty-four thousand, three hundred forty-one".

Divisors: 1 3 1901 5703 26302147 78906441 50000381447 150001144341