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15000241141 is a prime number
BaseRepresentation
bin11011111100001010…
…11000001111110101
31102201101121012110201
431332011120033311
5221210030204031
610520243120501
71040501642314
oct157605301765
942641535421
1015000241141
1163a8277206
122aa7673131
131550901a42
14a2428827b
155cbd60d61
hex37e1583f5

15000241141 has 2 divisors, whose sum is σ = 15000241142. Its totient is φ = 15000241140.

The previous prime is 15000241103. The next prime is 15000241169. The reversal of 15000241141 is 14114200051.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10054072900 + 4946168241 = 100270^2 + 70329^2 .

It is a cyclic number.

It is not a de Polignac number, because 15000241141 - 27 = 15000241013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15000241441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7500120570 + 7500120571.

It is an arithmetic number, because the mean of its divisors is an integer number (7500120571).

Almost surely, 215000241141 is an apocalyptic number.

It is an amenable number.

15000241141 is a deficient number, since it is larger than the sum of its proper divisors (1).

15000241141 is an equidigital number, since it uses as much as digits as its factorization.

15000241141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 160, while the sum is 19.

Adding to 15000241141 its reverse (14114200051), we get a palindrome (29114441192).

The spelling of 15000241141 in words is "fifteen billion, two hundred forty-one thousand, one hundred forty-one".