150004803334973 has 2 divisors, whose sum is σ = 150004803334974. Its totient is φ = 150004803334972.

The previous prime is 150004803334963. The next prime is 150004803334999. The reversal of 150004803334973 is 379433308400051.

150004803334973 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 148419324466009 + 1585478868964 = 12182747^2 + 1259158^2 .

It is an emirp because it is prime and its reverse (379433308400051) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-150004803334973 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (150004803334963) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75002401667486 + 75002401667487.

It is an arithmetic number, because the mean of its divisors is an integer number (75002401667487).

Almost surely, 2^{150004803334973} is an apocalyptic number.

It is an amenable number.

150004803334973 is a deficient number, since it is larger than the sum of its proper divisors (1).

150004803334973 is an equidigital number, since it uses as much as digits as its factorization.

150004803334973 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3265920, while the sum is 50.

The spelling of 150004803334973 in words is "one hundred fifty trillion, four billion, eight hundred three million, three hundred thirty-four thousand, nine hundred seventy-three".