1500113557 has 2 divisors, whose sum is σ = 1500113558. Its totient is φ = 1500113556.

The previous prime is 1500113551. The next prime is 1500113561. The reversal of 1500113557 is 7553110051.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1232431236 + 267682321 = 35106^2 + 16361^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1500113557 is a prime.

It is a super-3 number, since 3×1500113557³ (a number of 29 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1500113551) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 750056778 + 750056779.

It is an arithmetic number, because the mean of its divisors is an integer number (750056779).

Almost surely, 2^1500113557 is an apocalyptic number.

It is an amenable number.

1500113557 is a deficient number, since it is larger than the sum of its proper divisors (1).

1500113557 is an equidigital number, since it uses as much as digits as its factorization.

1500113557 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2625, while the sum is 28.

The square root of 1500113557 is about 38731.2994488953. The cubic root of 1500113557 is about 1144.7431285611.

The spelling of 1500113557 in words is "one billion, five hundred million, one hundred thirteen thousand, five hundred fifty-seven".