Base | Representation |
---|---|
bin | 1000101110110101110… |
… | …1001001010111001111 |
3 | 112100012122102012110222 |
4 | 2023231131021113033 |
5 | 4424211224310113 |
6 | 152525341221555 |
7 | 13560312104261 |
oct | 2135535112717 |
9 | 470178365428 |
10 | 150012728783 |
11 | 58690302505 |
12 | 250a6b618bb |
13 | 111b90b8098 |
14 | 7391345b31 |
15 | 3d7ec95e08 |
hex | 22ed7495cf |
150012728783 has 2 divisors, whose sum is σ = 150012728784. Its totient is φ = 150012728782.
The previous prime is 150012728759. The next prime is 150012728797. The reversal of 150012728783 is 387827210051.
It is a strong prime.
It is an emirp because it is prime and its reverse (387827210051) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 150012728783 - 28 = 150012728527 is a prime.
It is a super-2 number, since 2×1500127287832 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (150012728483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75006364391 + 75006364392.
It is an arithmetic number, because the mean of its divisors is an integer number (75006364392).
Almost surely, 2150012728783 is an apocalyptic number.
150012728783 is a deficient number, since it is larger than the sum of its proper divisors (1).
150012728783 is an equidigital number, since it uses as much as digits as its factorization.
150012728783 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 188160, while the sum is 44.
The spelling of 150012728783 in words is "one hundred fifty billion, twelve million, seven hundred twenty-eight thousand, seven hundred eighty-three".
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