Base | Representation |
---|---|
bin | 100010000111000110010101… |
… | …001010110011101111001011 |
3 | 201200011220111101011210102221 |
4 | 202013012111022303233023 |
5 | 124130422324310224043 |
6 | 1251022515312434511 |
7 | 43412455345032235 |
oct | 4207062512635713 |
9 | 650156441153387 |
10 | 150021415320523 |
11 | 4388a7a799756a |
12 | 149ab1a4548a37 |
13 | 6592c605277c6 |
14 | 290910a681255 |
15 | 12526045698ed |
hex | 8871952b3bcb |
150021415320523 has 2 divisors, whose sum is σ = 150021415320524. Its totient is φ = 150021415320522.
The previous prime is 150021415320487. The next prime is 150021415320529. The reversal of 150021415320523 is 325023514120051.
150021415320523 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-150021415320523 is a prime.
It is not a weakly prime, because it can be changed into another prime (150021415320529) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75010707660261 + 75010707660262.
It is an arithmetic number, because the mean of its divisors is an integer number (75010707660262).
Almost surely, 2150021415320523 is an apocalyptic number.
150021415320523 is a deficient number, since it is larger than the sum of its proper divisors (1).
150021415320523 is an equidigital number, since it uses as much as digits as its factorization.
150021415320523 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36000, while the sum is 34.
Adding to 150021415320523 its reverse (325023514120051), we get a palindrome (475044929440574).
The spelling of 150021415320523 in words is "one hundred fifty trillion, twenty-one billion, four hundred fifteen million, three hundred twenty thousand, five hundred twenty-three".
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