Base | Representation |
---|---|
bin | 1000101110111010100… |
… | …0100111100010110111 |
3 | 112100021000122100121102 |
4 | 2023232220213202313 |
5 | 4424231310410312 |
6 | 152531325240315 |
7 | 13560642214643 |
oct | 2135650474267 |
9 | 470230570542 |
10 | 150032513207 |
11 | 586a0495875 |
12 | 250b170309b |
13 | 111c0224345 |
14 | 7393c15c23 |
15 | 3d818a2ec2 |
hex | 22eea278b7 |
150032513207 has 2 divisors, whose sum is σ = 150032513208. Its totient is φ = 150032513206.
The previous prime is 150032513179. The next prime is 150032513233. The reversal of 150032513207 is 702315230051.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 150032513207 - 26 = 150032513143 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 150032513207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (150032513237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75016256603 + 75016256604.
It is an arithmetic number, because the mean of its divisors is an integer number (75016256604).
Almost surely, 2150032513207 is an apocalyptic number.
150032513207 is a deficient number, since it is larger than the sum of its proper divisors (1).
150032513207 is an equidigital number, since it uses as much as digits as its factorization.
150032513207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6300, while the sum is 29.
Adding to 150032513207 its reverse (702315230051), we get a palindrome (852347743258).
The spelling of 150032513207 in words is "one hundred fifty billion, thirty-two million, five hundred thirteen thousand, two hundred seven".
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