150040233319 has 2 divisors, whose sum is σ = 150040233320. Its totient is φ = 150040233318.

The previous prime is 150040233311. The next prime is 150040233323. The reversal of 150040233319 is 913332040051.

150040233319 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (913332040051) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 150040233319 - 2³ = 150040233311 is a prime.

It is a super-2 number, since 2×150040233319² (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (150040233311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75020116659 + 75020116660.

It is an arithmetic number, because the mean of its divisors is an integer number (75020116660).

Almost surely, 2^150040233319 is an apocalyptic number.

150040233319 is a deficient number, since it is larger than the sum of its proper divisors (1).

150040233319 is an equidigital number, since it uses as much as digits as its factorization.

150040233319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9720, while the sum is 31.

The spelling of 150040233319 in words is "one hundred fifty billion, forty million, two hundred thirty-three thousand, three hundred nineteen".