Base | Representation |
---|---|
bin | 11011111100110000… |
… | …11111001001010011 |
3 | 1102201202000200111212 |
4 | 31332120133021103 |
5 | 221212321001011 |
6 | 10520542330335 |
7 | 1040562343634 |
oct | 157630371123 |
9 | 42652020455 |
10 | 15005250131 |
11 | 6400088573 |
12 | 2aa92899ab |
13 | 1551966941 |
14 | a24bcd88b |
15 | 5cc50008b |
hex | 37e61f253 |
15005250131 has 16 divisors (see below), whose sum is σ = 15391231200. Its totient is φ = 14623435008.
The previous prime is 15005250109. The next prime is 15005250149. The reversal of 15005250131 is 13105250051.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 15005250131 - 230 = 13931508307 is a prime.
It is a super-3 number, since 3×150052501313 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 15005250097 and 15005250106.
It is not an unprimeable number, because it can be changed into a prime (15005250191) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5402015 + ... + 5404791.
It is an arithmetic number, because the mean of its divisors is an integer number (961951950).
Almost surely, 215005250131 is an apocalyptic number.
15005250131 is a deficient number, since it is larger than the sum of its proper divisors (385981069).
15005250131 is a wasteful number, since it uses less digits than its factorization.
15005250131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3478.
The product of its (nonzero) digits is 750, while the sum is 23.
The spelling of 15005250131 in words is "fifteen billion, five million, two hundred fifty thousand, one hundred thirty-one".
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