Base | Representation |
---|---|
bin | 100010000111100100000100… |
… | …001101000011111110111011 |
3 | 201200021221220110122121000102 |
4 | 202013210010031003332323 |
5 | 124131433221244002103 |
6 | 1251045315404430015 |
7 | 43414665502320101 |
oct | 4207440415037673 |
9 | 650257813577012 |
10 | 150053342953403 |
11 | 438a22a123a71a |
12 | 149b5414b4830b |
13 | 6595c7b079b76 |
14 | 290a898b07c71 |
15 | 125337250de88 |
hex | 887904343fbb |
150053342953403 has 2 divisors, whose sum is σ = 150053342953404. Its totient is φ = 150053342953402.
The previous prime is 150053342953363. The next prime is 150053342953447. The reversal of 150053342953403 is 304359243350051.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 150053342953403 - 28 = 150053342953147 is a prime.
It is not a weakly prime, because it can be changed into another prime (150053342953103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75026671476701 + 75026671476702.
It is an arithmetic number, because the mean of its divisors is an integer number (75026671476702).
Almost surely, 2150053342953403 is an apocalyptic number.
150053342953403 is a deficient number, since it is larger than the sum of its proper divisors (1).
150053342953403 is an equidigital number, since it uses as much as digits as its factorization.
150053342953403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2916000, while the sum is 47.
The spelling of 150053342953403 in words is "one hundred fifty trillion, fifty-three billion, three hundred forty-two million, nine hundred fifty-three thousand, four hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •