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150055411811 is a prime number
BaseRepresentation
bin1000101110111111111…
…1111110000001100011
3112100022121201201120212
42023233333332001203
54424303141134221
6152533504124335
713561340645504
oct2135777760143
9470277651525
10150055411811
1158702405938
12250b93066ab
13111c4bb0c06
147396c96bab
153d838c7b5b
hex22efffe063

150055411811 has 2 divisors, whose sum is σ = 150055411812. Its totient is φ = 150055411810.

The previous prime is 150055411783. The next prime is 150055411837. The reversal of 150055411811 is 118114550051.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-150055411811 is a prime.

It is a super-2 number, since 2×1500554118112 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (150055411841) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75027705905 + 75027705906.

It is an arithmetic number, because the mean of its divisors is an integer number (75027705906).

Almost surely, 2150055411811 is an apocalyptic number.

150055411811 is a deficient number, since it is larger than the sum of its proper divisors (1).

150055411811 is an equidigital number, since it uses as much as digits as its factorization.

150055411811 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4000, while the sum is 32.

Adding to 150055411811 its reverse (118114550051), we get a palindrome (268169961862).

The spelling of 150055411811 in words is "one hundred fifty billion, fifty-five million, four hundred eleven thousand, eight hundred eleven".