Base | Representation |
---|---|
bin | 1000101110111111111… |
… | …1111110000001100011 |
3 | 112100022121201201120212 |
4 | 2023233333332001203 |
5 | 4424303141134221 |
6 | 152533504124335 |
7 | 13561340645504 |
oct | 2135777760143 |
9 | 470277651525 |
10 | 150055411811 |
11 | 58702405938 |
12 | 250b93066ab |
13 | 111c4bb0c06 |
14 | 7396c96bab |
15 | 3d838c7b5b |
hex | 22efffe063 |
150055411811 has 2 divisors, whose sum is σ = 150055411812. Its totient is φ = 150055411810.
The previous prime is 150055411783. The next prime is 150055411837. The reversal of 150055411811 is 118114550051.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-150055411811 is a prime.
It is a super-2 number, since 2×1500554118112 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (150055411841) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75027705905 + 75027705906.
It is an arithmetic number, because the mean of its divisors is an integer number (75027705906).
Almost surely, 2150055411811 is an apocalyptic number.
150055411811 is a deficient number, since it is larger than the sum of its proper divisors (1).
150055411811 is an equidigital number, since it uses as much as digits as its factorization.
150055411811 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4000, while the sum is 32.
Adding to 150055411811 its reverse (118114550051), we get a palindrome (268169961862).
The spelling of 150055411811 in words is "one hundred fifty billion, fifty-five million, four hundred eleven thousand, eight hundred eleven".
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