Base | Representation |
---|---|
bin | 1000101110111111111… |
… | …1111111111001011111 |
3 | 112100022121202010010011 |
4 | 2023233333333321133 |
5 | 4424303141410422 |
6 | 152533504224051 |
7 | 13561341010051 |
oct | 2135777777137 |
9 | 470277663104 |
10 | 150055419487 |
11 | 58702410686 |
12 | 250b930b027 |
13 | 111c4bb455c |
14 | 7396c998d1 |
15 | 3d838ca077 |
hex | 22effffe5f |
150055419487 has 2 divisors, whose sum is σ = 150055419488. Its totient is φ = 150055419486.
The previous prime is 150055419473. The next prime is 150055419533. The reversal of 150055419487 is 784914550051.
It is a weak prime.
It is an emirp because it is prime and its reverse (784914550051) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 150055419487 - 231 = 147907935839 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 150055419487.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (150055419457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75027709743 + 75027709744.
It is an arithmetic number, because the mean of its divisors is an integer number (75027709744).
Almost surely, 2150055419487 is an apocalyptic number.
150055419487 is a deficient number, since it is larger than the sum of its proper divisors (1).
150055419487 is an equidigital number, since it uses as much as digits as its factorization.
150055419487 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008000, while the sum is 49.
The spelling of 150055419487 in words is "one hundred fifty billion, fifty-five million, four hundred nineteen thousand, four hundred eighty-seven".
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