Base | Representation |
---|---|
bin | 1000101111000000000… |
… | …0010011100001111111 |
3 | 112100022121220012102112 |
4 | 2023300000103201333 |
5 | 4424303201444103 |
6 | 152533510044235 |
7 | 13561341463361 |
oct | 2136000234177 |
9 | 470277805375 |
10 | 150055499903 |
11 | 58702466041 |
12 | 250b934967b |
13 | 111c4c1203a |
14 | 7396cbad31 |
15 | 3d838e3cd8 |
hex | 22f001387f |
150055499903 has 2 divisors, whose sum is σ = 150055499904. Its totient is φ = 150055499902.
The previous prime is 150055499857. The next prime is 150055499987. The reversal of 150055499903 is 309994550051.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-150055499903 is a prime.
It is a super-2 number, since 2×1500554999032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (150055499303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75027749951 + 75027749952.
It is an arithmetic number, because the mean of its divisors is an integer number (75027749952).
Almost surely, 2150055499903 is an apocalyptic number.
150055499903 is a deficient number, since it is larger than the sum of its proper divisors (1).
150055499903 is an equidigital number, since it uses as much as digits as its factorization.
150055499903 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1093500, while the sum is 50.
The spelling of 150055499903 in words is "one hundred fifty billion, fifty-five million, four hundred ninety-nine thousand, nine hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.060 sec. • engine limits •