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150083326333 is a prime number
BaseRepresentation
bin1000101111000110101…
…0011101000101111101
3112100101120020221010001
42023301222131011331
54424332312420313
6152540342314301
713562130140113
oct2136152350575
9470346227101
10150083326333
1158717141496
1225106728991
13111ca905895
14739a881ab3
153d8608dadd
hex22f1a9d17d

150083326333 has 2 divisors, whose sum is σ = 150083326334. Its totient is φ = 150083326332.

The previous prime is 150083326273. The next prime is 150083326399. The reversal of 150083326333 is 333623380051.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 75590903844 + 74492422489 = 274938^2 + 272933^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-150083326333 is a prime.

It is a super-3 number, since 3×1500833263333 (a number of 35 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 150083326292 and 150083326301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (150083366333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75041663166 + 75041663167.

It is an arithmetic number, because the mean of its divisors is an integer number (75041663167).

Almost surely, 2150083326333 is an apocalyptic number.

It is an amenable number.

150083326333 is a deficient number, since it is larger than the sum of its proper divisors (1).

150083326333 is an equidigital number, since it uses as much as digits as its factorization.

150083326333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 116640, while the sum is 37.

The spelling of 150083326333 in words is "one hundred fifty billion, eighty-three million, three hundred twenty-six thousand, three hundred thirty-three".