15009974983 has 2 divisors, whose sum is σ = 15009974984. Its totient is φ = 15009974982.

The previous prime is 15009974927. The next prime is 15009974999. The reversal of 15009974983 is 38947990051.

It is a strong prime.

It is an emirp because it is prime and its reverse (38947990051) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-15009974983 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15009974923) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7504987491 + 7504987492.

It is an arithmetic number, because the mean of its divisors is an integer number (7504987492).

Almost surely, 2^15009974983 is an apocalyptic number.

15009974983 is a deficient number, since it is larger than the sum of its proper divisors (1).

15009974983 is an equidigital number, since it uses as much as digits as its factorization.

15009974983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2449440, while the sum is 55.

It can be divided in two parts, 1500997 and 4983, that added together give a triangular number (1505980 = T₁₇₃₅).

The spelling of 15009974983 in words is "fifteen billion, nine million, nine hundred seventy-four thousand, nine hundred eighty-three".