Base | Representation |
---|---|
bin | 1000101111001101110… |
… | …1101110001111100001 |
3 | 112100110200010002202221 |
4 | 2023303131232033201 |
5 | 4424413031340022 |
6 | 152543342111041 |
7 | 13562645030545 |
oct | 2136335561741 |
9 | 470420102687 |
10 | 150113543137 |
11 | 587321aa858 |
12 | 2511487b481 |
13 | 11203c5544c |
14 | 73a08a9a25 |
15 | 3d88a5bcc7 |
hex | 22f376e3e1 |
150113543137 has 2 divisors, whose sum is σ = 150113543138. Its totient is φ = 150113543136.
The previous prime is 150113543087. The next prime is 150113543189. The reversal of 150113543137 is 731345311051.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 150016007761 + 97535376 = 387319^2 + 9876^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-150113543137 is a prime.
It is not a weakly prime, because it can be changed into another prime (150113543737) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75056771568 + 75056771569.
It is an arithmetic number, because the mean of its divisors is an integer number (75056771569).
Almost surely, 2150113543137 is an apocalyptic number.
It is an amenable number.
150113543137 is a deficient number, since it is larger than the sum of its proper divisors (1).
150113543137 is an equidigital number, since it uses as much as digits as its factorization.
150113543137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18900, while the sum is 34.
Adding to 150113543137 its reverse (731345311051), we get a palindrome (881458854188).
The spelling of 150113543137 in words is "one hundred fifty billion, one hundred thirteen million, five hundred forty-three thousand, one hundred thirty-seven".
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