Base | Representation |
---|---|
bin | 1000101111001110000… |
… | …0110101010010101111 |
3 | 112100110201122112011121 |
4 | 2023303200311102233 |
5 | 4424413233432242 |
6 | 152543411401411 |
7 | 13562654664544 |
oct | 2136340652257 |
9 | 470421575147 |
10 | 150114358447 |
11 | 58732707369 |
12 | 25114bb3267 |
13 | 1120417c591 |
14 | 73a0a3cbcb |
15 | 3d88b6d667 |
hex | 22f38354af |
150114358447 has 2 divisors, whose sum is σ = 150114358448. Its totient is φ = 150114358446.
The previous prime is 150114358349. The next prime is 150114358453. The reversal of 150114358447 is 744853411051.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 150114358447 - 215 = 150114325679 is a prime.
It is a super-2 number, since 2×1501143584472 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (150114358847) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75057179223 + 75057179224.
It is an arithmetic number, because the mean of its divisors is an integer number (75057179224).
Almost surely, 2150114358447 is an apocalyptic number.
150114358447 is a deficient number, since it is larger than the sum of its proper divisors (1).
150114358447 is an equidigital number, since it uses as much as digits as its factorization.
150114358447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 268800, while the sum is 43.
Adding to 150114358447 its reverse (744853411051), we get a palindrome (894967769498).
The spelling of 150114358447 in words is "one hundred fifty billion, one hundred fourteen million, three hundred fifty-eight thousand, four hundred forty-seven".
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