Base | Representation |
---|---|
bin | 100010001000101110100011… |
… | …001101010111100111101011 |
3 | 201200120121100012121122201221 |
4 | 202020232203031113213223 |
5 | 124134241014411210012 |
6 | 1251150143422522511 |
7 | 43423526425224553 |
oct | 4210564315274753 |
9 | 650517305548657 |
10 | 150133320022507 |
11 | 43923202204448 |
12 | 14a08a15136437 |
13 | 65a06855134b3 |
14 | 29106c47d4163 |
15 | 12554a399d507 |
hex | 888ba33579eb |
150133320022507 has 2 divisors, whose sum is σ = 150133320022508. Its totient is φ = 150133320022506.
The previous prime is 150133320022481. The next prime is 150133320022529. The reversal of 150133320022507 is 705220023331051.
It is a strong prime.
It is an emirp because it is prime and its reverse (705220023331051) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 150133320022507 - 211 = 150133320020459 is a prime.
It is not a weakly prime, because it can be changed into another prime (150133320022537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75066660011253 + 75066660011254.
It is an arithmetic number, because the mean of its divisors is an integer number (75066660011254).
Almost surely, 2150133320022507 is an apocalyptic number.
150133320022507 is a deficient number, since it is larger than the sum of its proper divisors (1).
150133320022507 is an equidigital number, since it uses as much as digits as its factorization.
150133320022507 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 37800, while the sum is 34.
Adding to 150133320022507 its reverse (705220023331051), we get a palindrome (855353343353558).
The spelling of 150133320022507 in words is "one hundred fifty trillion, one hundred thirty-three billion, three hundred twenty million, twenty-two thousand, five hundred seven".
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