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15013998997 is a prime number
BaseRepresentation
bin11011111101110011…
…10111000110010101
31102202100111011200221
431332321313012111
5221222040431442
610521454034341
71041026612554
oct157671670625
942670434627
1015013998997
116405013738
122ab01a89b1
13155370ab9a
14a26029d9b
155cd17c467
hex37ee77195

15013998997 has 2 divisors, whose sum is σ = 15013998998. Its totient is φ = 15013998996.

The previous prime is 15013998983. The next prime is 15013999003. The reversal of 15013998997 is 79989931051.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14513984676 + 500014321 = 120474^2 + 22361^2 .

It is an emirp because it is prime and its reverse (79989931051) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15013998997 is a prime.

It is a super-3 number, since 3×150139989973 (a number of 32 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15013968997) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7506999498 + 7506999499.

It is an arithmetic number, because the mean of its divisors is an integer number (7506999499).

Almost surely, 215013998997 is an apocalyptic number.

It is an amenable number.

15013998997 is a deficient number, since it is larger than the sum of its proper divisors (1).

15013998997 is an equidigital number, since it uses as much as digits as its factorization.

15013998997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5511240, while the sum is 61.

The spelling of 15013998997 in words is "fifteen billion, thirteen million, nine hundred ninety-eight thousand, nine hundred ninety-seven".